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Math·Advanced Math·Nonlinear functions

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The equation $N(m)=63(Q{)}^{\frac{m}{6}}$ gives the predicted population $N(m)$, in thousands, of a certain bacteria colony $m$ minutes after the initial measurement, where $Q$ is a constant greater than 1. The predicted population increases by $p\%$ every $180$ seconds. What is the value of $p$ in terms of $Q$?

A

$100(Q^{30}-1)$

B

$100(Q^{\frac{1}{2}}-1)$

C

$100(Q^{30}+1)$

D

$100(Q^{\frac{1}{2}}+1)$