$h=\frac{9(v-273.15)}{5}+32$. The equation gives the corresponding te…

Question

Prompt

h = \frac{9 ( v - 273.15 )}{5} + 32

. The equation gives the corresponding temperature

h

, in degrees Fahrenheit, of any substance that has a temperature of

v

kelvins, where

v > 0

. If a substance has a temperature of

467.33

degrees Fahrenheit, what is the corresponding temperature, in kelvins, of this substance?