The function is defined by f(x)=6(x−2)(x2−k), where k is a constant. In the xy-plane, the graph of y=f(x) passes through the point (−8,0). What is the value of f(0)?
1
768
The function is defined by \(f(x)=6(x-2)(x^2-k)\), where \(k\) is a c… | Math SAT Question | Ronan SAT