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Math·Algebra·Linear equations in one variable

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The equation $h=\frac{9(v-273.15)}{5}+32$ gives the corresponding temperature $h$, in degrees Fahrenheit, of any substance that has a temperature of $v$ kelvins, where $v>0$. If a substance has a temperature of $809.33\text{ degrees Fahrenheit}$, what is the corresponding temperature, in kelvins, of this substance?

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