The equation $N(m)=65(Q)^{\frac{m}{6}}$ gives the predicted populatio…

Question

Prompt

The equation

N (m) = 65 (Q)^{\frac{m}{6}}

gives the predicted population

N (m)

, in thousands, of a certain bacteria colony m minutes after the initial measurement, where Q is a constant greater than 1. The predicted population increases by p% every 180 seconds. What is the value of p in terms of Q?

100 (Q^{\frac{1}{2}} + 1)

100 (Q^{30} + 1)

100 (Q^{\frac{1}{2}} - 1)

100 (Q^{30} - 1)